0=2x^2+9x-2700

Solution for 0=2x^2+9x-2700 equation:

0=2x^2+9x-2700

We move all terms to the left:

0-(2x^2+9x-2700)=0

We add all the numbers together, and all the variables

-(2x^2+9x-2700)=0

We get rid of parentheses

-2x^2-9x+2700=0

a = -2; b = -9; c = +2700;
Δ = b2-4ac
Δ = -92-4·(-2)·2700
Δ = 21681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{21681}=\sqrt{9*2409}=\sqrt{9}*\sqrt{2409}=3\sqrt{2409}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-3\sqrt{2409}}{2*-2}=\frac{9-3\sqrt{2409}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+3\sqrt{2409}}{2*-2}=\frac{9+3\sqrt{2409}}{-4}
$